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A girl is 28 years younger than her fath...

A girl is `28` years younger than her father. The sum of their ages is `50` years. Find the ages of the girl and her father.

A

`11, 39`

B

`12, 40`

C

`13, 34`

D

`14, 44`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these instructions: ### Step 1: Define the Variables Let the girl's age be represented by \( x \). ### Step 2: Express the Father's Age Since the girl is 28 years younger than her father, we can express her father's age as: \[ \text{Father's age} = x + 28 \] ### Step 3: Set Up the Equation According to the problem, the sum of their ages is 50 years. Therefore, we can set up the following equation: \[ x + (x + 28) = 50 \] ### Step 4: Simplify the Equation Now, we simplify the equation: \[ x + x + 28 = 50 \] This simplifies to: \[ 2x + 28 = 50 \] ### Step 5: Isolate the Variable Next, we need to isolate \( x \). We can do this by subtracting 28 from both sides: \[ 2x = 50 - 28 \] \[ 2x = 22 \] ### Step 6: Solve for \( x \) Now, divide both sides by 2 to find \( x \): \[ x = \frac{22}{2} \] \[ x = 11 \] ### Step 7: Find the Father's Age Now that we have the girl's age, we can find the father's age: \[ \text{Father's age} = x + 28 = 11 + 28 = 39 \] ### Conclusion The girl's age is \( 11 \) years, and her father's age is \( 39 \) years. ### Summary of the Solution - Girl's age: \( 11 \) years - Father's age: \( 39 \) years ---
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