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The value of sqrt(176+sqrt(2401)) is...

The value of `sqrt(176+sqrt(2401))` is

A

`14`

B

`15`

C

`16`

D

`17`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( \sqrt{176 + \sqrt{2401}} \), we will follow these steps: ### Step 1: Calculate \( \sqrt{2401} \) First, we need to find the square root of 2401. To do this, we can factor 2401: - 2401 can be divided by 7: - \( 2401 \div 7 = 343 \) - 343 can again be divided by 7: - \( 343 \div 7 = 49 \) - 49 can be divided by 7: - \( 49 \div 7 = 7 \) - Finally, 7 can be divided by 7: - \( 7 \div 7 = 1 \) Thus, we have: \[ 2401 = 7^4 \] Taking the square root: \[ \sqrt{2401} = \sqrt{7^4} = 7^2 = 49 \] ### Step 2: Substitute \( \sqrt{2401} \) back into the expression Now we substitute \( \sqrt{2401} \) back into the original expression: \[ \sqrt{176 + \sqrt{2401}} = \sqrt{176 + 49} \] ### Step 3: Calculate \( 176 + 49 \) Now we add 176 and 49: \[ 176 + 49 = 225 \] ### Step 4: Calculate \( \sqrt{225} \) Next, we need to find the square root of 225: - We can factor 225: - \( 225 = 15 \times 15 \) Thus: \[ \sqrt{225} = 15 \] ### Final Answer Therefore, the value of \( \sqrt{176 + \sqrt{2401}} \) is \( 15 \). ---
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NCERT EXEMPLAR-SQUARE - SQUARE ROOT AND CUBE-CUBE ROOT-Exercise
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