In a solid if F = V = 5, then the number of edges in this shape is

Options

A. 6
B. 4
C. 8
D. 2

Answer

To find the number of edges in a solid where the number of faces (F) and vertices (V) are both equal to 5, we can use Euler's formula for polyhedra, which states:

\[ F + V = E + 2 \]

where:
- \( F \) = number of faces
- \( V \) = number of vertices
- \( E \) = number of edges

### Step-by-Step Solution:

1. **Identify the values of F and V**:
Given that \( F = 5 \) and \( V = 5 \).

2. **Substitute the values into Euler's formula**:
We substitute \( F \) and \( V \) into the formula:
\[ 5 + 5 = E + 2 \]

3. **Simplify the equation**:
This simplifies to:
\[ 10 = E + 2 \]

4. **Isolate E**:
To find \( E \), subtract 2 from both sides:
\[ E = 10 - 2 \]
\[ E = 8 \]

5. **Conclusion**:
Therefore, the number of edges \( E \) in this solid shape is 8.

### Final Answer:
The number of edges in the solid shape is **8**.