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(x + a) (x + b) = x^(2) + (a + b)x + ....

(x + a) (x + b) = `x^(2)` + (a + b)x + ________.

A

`ab^2`

B

`a^2b`

C

ab

D

`a^2b^2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \((x + a)(x + b) = x^2 + (a + b)x + \_\_\_\_\_\_\_\_\), we will expand the left-hand side and identify the missing term. ### Step-by-Step Solution: 1. **Write down the expression to be expanded**: \[ (x + a)(x + b) \] 2. **Use the distributive property (FOIL method)**: - First, multiply the first terms: \(x \cdot x = x^2\) - Outer: \(x \cdot b = bx\) - Inner: \(a \cdot x = ax\) - Last: \(a \cdot b = ab\) Putting these together, we have: \[ x^2 + bx + ax + ab \] 3. **Combine like terms**: - The terms \(bx\) and \(ax\) can be combined: \[ x^2 + (a + b)x + ab \] 4. **Identify the missing term**: - From the expression \(x^2 + (a + b)x + ab\), we see that the blank in the original equation corresponds to \(ab\). Thus, the complete equation is: \[ (x + a)(x + b) = x^2 + (a + b)x + ab \] ### Final Answer: The missing term is \(ab\). ---
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