The sum of areas of two squares with sides 4a and 4b is _______.

The side of a square exceeds the side of the another square by 4cm and the sum of the areas of the two squares is 400 sq.cm. Find the dimensions of the squares.

The sum of the areas of two squares is 157 m^(2) . If the sum of their perimeters is 68 m , find the sides of the two squares .

The sum of the areas of two squares is 640 m^(2) . If the difference in their perimeters be 64 m, find the sides of the two squares.

The length of side of a square is 'a' metre. A second square is formed by joining the middle points of this square. Then a third square is formed by joining the middle points of the sides of the second square and so on. Then, the sum of the areas of squares which carried upto infinity, is

The ratio of the area of a square of side a and that of an equilateral triangle of side a, is 2:1 (b) 2:sqrt(3)4:3( d) 4:sqrt(3)

What happens to the area of a square when its side is increased by 4 times ?

The ratio of the areas of two squares is 1:4 .if the area of the first is 9 sq. units . The area of the first square is ____ ( in sq. units)

ABCD is a square of area of 4 square units which is divided into 4 non overlapping triangles as shown in figure, then sum of perimieters of the triangles so formed is

Find the side of a square whose area is equal to the area of a rectangle with sides 6.4m and 2.5m.