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NCERT EXEMPLAR-EXPONENTS AND POWERS-EXERCISE
- Very large numbers can be expressed in standard form by using exponent...
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- By multiplying (10)^(5) by (10)^(-10) we get.
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- [(2/13)^(-6)-:(2/12)^(3)]^(3)xx(2/13)^(-9)=
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- Find the value [4^(-1)+3^(-1)+6^(-2)]^(-1).
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- [2^(-1)+3^(-1)+4^(-1)]^(0)=
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- The standard from of (1/100000000) is .
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- The standard form of 12340000 is .
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- The usual form of 3.41xx10^(6) is .
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- The usual form of 2.39461xx10^(6) is .
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- If 36=6xx6=6^(2) then 1/36 expressed as a power with the base 6 is .
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- By multiplying (5/3)^(4) bywe get 5^(4).
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- 3^(5)-:3^(-6) can be simplified as .
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- The value of 3xx10^(-7) is equal to .
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- To add the numbers given in standard form we first convert them into m...
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- The standard form of 32,50,00,00,000 is .
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- The standard form for 0.000000008 is .
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- The usual form for 2.3xx10^(-10) is .
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- On dividing 8^(5) by we get 8.
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- On multiplying by 2^(-5) we get 2^(5).
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- The value of [3^(-1)xx4^(-1)]^(2) is .
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