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NCERT EXEMPLAR-EXPONENTS AND POWERS-EXERCISE
- The usual form of 2.39461xx10^(6) is .
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- If 36=6xx6=6^(2) then 1/36 expressed as a power with the base 6 is .
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- By multiplying (5/3)^(4) bywe get 5^(4).
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- 3^(5)-:3^(-6) can be simplified as .
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- The value of 3xx10^(-7) is equal to .
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- To add the numbers given in standard form we first convert them into m...
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- The standard form of 32,50,00,00,000 is .
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- The standard form for 0.000000008 is .
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- The usual form for 2.3xx10^(-10) is .
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- On dividing 8^(5) by we get 8.
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- On multiplying by 2^(-5) we get 2^(5).
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- The value of [3^(-1)xx4^(-1)]^(2) is .
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- The value of [2^(-1)xx3^(-1)]^(-1) is .
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- By solving (6^(@)-7^(@))xx(6^(@)+7^(@)) we get .
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- The expression for 3^(5) with a negative exponent is .
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- The value for (-7)^(6)-:7^(6) is .
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- The value of [1^(-2)+2^(-2)+3^(-2)]xx6^(2) is .
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- The multiplicative inverse of (-4)^(-2) is (4)^(-2).
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- The multiplicative inverse of (3/2)^(2) is not equal to (2/3)^(-2).
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- 10^(-2)=1/100
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