Topper's Solved these Questions
Similar Questions
Explore conceptually related problems
NCERT EXEMPLAR-EXPONENTS AND POWERS-EXERCISE
- To add the numbers given in standard form we first convert them into m...
Text Solution
|
- The standard form of 32,50,00,00,000 is .
Text Solution
|
- The standard form for 0.000000008 is .
Text Solution
|
- The usual form for 2.3xx10^(-10) is .
Text Solution
|
- On dividing 8^(5) by we get 8.
Text Solution
|
- On multiplying by 2^(-5) we get 2^(5).
Text Solution
|
- The value of [3^(-1)xx4^(-1)]^(2) is .
Text Solution
|
- The value of [2^(-1)xx3^(-1)]^(-1) is .
Text Solution
|
- By solving (6^(@)-7^(@))xx(6^(@)+7^(@)) we get .
Text Solution
|
- The expression for 3^(5) with a negative exponent is .
Text Solution
|
- The value for (-7)^(6)-:7^(6) is .
Text Solution
|
- The value of [1^(-2)+2^(-2)+3^(-2)]xx6^(2) is .
Text Solution
|
- The multiplicative inverse of (-4)^(-2) is (4)^(-2).
Text Solution
|
- The multiplicative inverse of (3/2)^(2) is not equal to (2/3)^(-2).
Text Solution
|
- 10^(-2)=1/100
Text Solution
|
- 24.58=2xx10+4xx1+5xx10+8xx100
Text Solution
|
- 329.25=3xx10^(2)+2xx10^(1)+9xx10^(@)+2xx10^(-1)+5xx10^(-2)
Text Solution
|
- (-5)^(2)xx(-5)^(-3)=(-5)^(-6)
Text Solution
|
- (-4)^(-4)xx(-4)^(-1)=(-4)^(x) find x.
Text Solution
|
- (2/3)^(-2)xx(2/3)^(-5)=(2/3)^(10)
Text Solution
|