`329.25=3xx10^(2)+2xx10^(1)+9xx10^(@)+2xx10^(-1)+5xx10^(-2)`

Write the numeral whose expanded form is given below: ( i ) 6 xx 10^(4)+3 xx 10^(3)+0 xx 10^(2)+7 xx 10^(1)+8 xx 10^(0) ( ii ) 9 xx 10^(6)+7 xx 10^(5)+0 xx 10^(4)+3 xx 10^(3)+2 xx 10^(2)+9 xx 10^(1)+6 xx 10^(0) ( iii ) 8 xx 10^(5)+6 xx 10^(4)+4 xx 10^(3)+2 xx 10^(2)+9 xx 10^(1)+6 xx 10^(0)

Find the number from each of the following expanded forms :(a) 8xx10^(4)+6xx10^(3)+0xx10^(2)+4xx10^(1)+5xx10^(0) (b) 4xx10^(5)+5xx10^(3)+3xx10^(2)+2xx10^(0)(c)3xx10^(4)+7xx10^(2)+5xx10^(0)

0.5xx10^(-4)xx0.3xx10^(-3)xx10

State True or False : 876543=8xx10^(5)+7xx10^(4)+6xx10^(3)+5xx10^(2)+4xx10^(1)+3xx10^(@)

Hardness of water is 200 ppm. The normality and molarity of CaCO_3 in the water is (a). 2xx10^(-6)(N,2xx10^(-6)M (b). 4xx10^(-2)N,2xx10^(-2)M (c). 4xx10^(-3)N,2xx10^(-3)M (d). 4xx10^(-1)N,2xx10^(-1)M

If 4003250 = 4 xx10^(x) + 3xx10^(y) + 2xx10^(z) + 5xx10^(w) , then x+y+z + w is equal to

At 800^(@)C the rate of reaction 2NO + H_(2) rarr N_(2) + H_(2)O Changes with the concentration of NO and H_(2) are [NO] in M " "[H_(2)]" in M "" "-(1)/(2) (d[NO])/(dt)" in M sec"^(-1) (i) 1.5xx10^(-4)" "4xx10^(-3)" "4.4xx10^(-4) (ii) 1.5xx10^(-4)" "2xx10^(-3)" "2.2xx10^(-4) (iii) 3.0xx10^(-4)" "2xx10^(-3)" "8.8xx10^(-4) (a) What is the order of this reaction ? (b) What is the rate equation for the reaction ? (c) What is the rate when [H_(2)]=1.5xx10^(-3)" M and "[NO]=1.1xx10^(-3) M ?

For a reaction 2NO(g) + 2H_(2)(g) rarr N_(2)(g)+2H_(2)O(g) the following data were obtained: |{:(,[NO] (mol L^(-1)),[H_(2)] (mol L^(-1)),"Rate" (mol L^(-1) s^(-1))),(1.,5 xx 10^(-3),2.5 xx 10^(-3),3 xx 10^(-5)),(2.,15 xx 10^(-3),2.5 xx 10^(-3),9xx10^(-5)),(3.,15 xx 10^(-3),10 xx 10^(-3),3.6 xx 10^(-4)):}| (a) Calculating the order of reactions. (b) Find the rate constant. (c ) Find the initial rate if [NO] = [H_(2)] = 8.0 xx 10^(-3) M

(2.4xx10^(3))-:(8xx10^(-2))=?3xx10^(-5)b3xx10^(4)c.3xx10^(5)d.30