Home
Class 12
PHYSICS
A parallel plate capacitor with air betw...

A parallel plate capacitor with air between the plates has capacitance of `9pF`. The separation between its plates is 'd'. The space between the plates is now filled with two dielectrics. One of the dielectrics has dielectric constant `k_1=3` and thickness `d/3` while the other one has dielectric constant `k_2=6` and thickness `(2d)/(3)`. Capacitance of the capacitor is now

Promotional Banner

Similar Questions

Explore conceptually related problems

A parallel plate capacitor with air between the plates has a capacitance C. If the distance between the plates is doubled and the space between the plates is filled with a dielectric of dielectric constant 6, then the capacitance will become.

A parallel plate capacitor with air between the plates has a capacitance of 10 pF. The capacitance, if the distance bgetween the plates is reduced by half and the space between tehm is filled with a substance of dielectric constant 4 is

A parallel plate capacitor with air inbetween the paltes has a capacitance of 8 pF. The separation between the plates is now reduced by half and the space between them is filled with a medium of dielectric constant 5. Calculate the new value of capacitance.

A parallel plate capacitor with air in between the plates has a capacitance of 8 pF . The separation between the plates is now reduced to half and the space between them is filled with a medium of dielectric constant 5. Calculate the value of capacitance in the second case.

A parallel plate capacitor with air between the plates has a capacitance of 8 pF. Calculate the capacitace if the distance between the plates is reduced by half and the space between them is filled with a substance of dielectric constant (epsilon_(r)=6)

A parallel plate capacitor with air between the plates has a capacitance of 8pF. The separation between the plates is now reduced by half and the space between them is filled with medium of dielectric constant 5. The value of capacitance of a capacitor in the second case is

A parallel plate capacitor of capacitance C is charged to a potential V and then disconnected with the battery. If separation between the plates is decreased by 50% and the space between the plates is filled with a dielectric slab of dielectric constant K=10 . then

A parallel plate air capacitor has a capacity of 2 pF. If the separation between its plates is doubled and a mica sheet is introduced between its plates, its capacity becomes 6 pF. What is the dielectric constant of mica?