The wavelength of the first spectral line in the Balmer series of hydrogen atom is `6561 A^(@)` . The wavelength of the second spectral line in the Balmer series of singly - ionized helium atom is

The wavelength of the spectral live the Balner series of hydrogen atom is 6561 A^(@) . The wavelength of the second spectralline in the Balmer series of singly - ionized belium atom is

The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. If the wavelength of the spectral line in the Balmer series of singly-ionized helium atom is 1215 when electron jumps from n_2 to n_1 , then n_2 and n_1 , are

The wavelength of the first spectral line of the Lyman series of hydrogen spectrum is

The wavelength of the third line of the Balmer series for a hydrogen atom is -

If the wavelength of the first line of the Balmer series of hydrogen atom is 656.1 nm the wavelngth of the second line of this series would be

If the wavelength of the first line of the Balmer series of hydrogen is 6561 Å , the wavelngth of the second line of the series should be

The wavelength of the ultraviolet region of the hydrogen spectrum is 122 nm. The wavelength of the second sperctral line in the Balmer series of singly ionized helium atom is (a) 1215 Å (b) 1640 Å (C ) 2430 Å (d) 4687 Å

If the wavelength of the firsr line of the Blamer series of hydrogen atom is 6561Å , the wavelength of the second line of the series should be

The wavelength of the first line of the Balmer series of hydrogen atom is lamda . The wavelength of the corresponding line line of doubly ionized lithium atom is