The rate constant of a reaction is `5xx10^(-8)` mole `litre^(-1)sec^(-1)` .How long it would take to change concentration for `4xx10^(-2) M` to `2xx10^(-2) M`?

The rate constant of a reaction is 1.2xx10^(-5)mol ^(-2)"litre"^(2) S^(-1) the order of the reaction is

The rate constant of a reaction is 3.25xx10^(-3) "mol"^(-2) "litre"^(2) "min"^(-1) The order of reaction is

A drop of solution (volume 0.10 ml) contains 6 xx 10^(–6)" mole of "H^(+) , if the rate constant of disappearance of H^(+) is 1 xx 10^(7)" mole litre"^(–1)" sec"^(–1) . How long would it take for H^(+) in drop to disappear ?

The rate constant fro a second order reaction is 8 xx 10^(-5) M^(-1) "min"^(-1) . How long will in take a 1 M solution to be reduced to 0.5 M

A drop of solution ("volume" =0.05 mL) contains 3xx10^(-2) mole of H^(+) . If the rate constant of disappearance of H^(+) is 1.0xx10^(2) mol litre^(-1) minute^(-1) . How long (in minutes) will it take to disappear all the H^(+) ions?