A small marble is projected with a velocity of `10 m//s` in a direction `45^(@)`from the y-direction on the smooth inclined plane. Calculate the magnitude `v` of its velocity of after `2 s` (Take `g = 10 m//s^(2))`

A small sphere is projected with velocity 5(m)/(s) in a direction 37^(@) from the horizontal y-axis on a smoother inclined plane. The motion of sphere takes plane in x-y plane. Magnitude of its velocity after 2 s is:

A small sphere is projected with a velocity of 3 ms^-1 in a direction 60^@ from the horizontal y - axis, on the smooth inclined plane (Fig. 5.197). The motion of sphere takes place in the x - y plane. Calculate the magnitude v of its velocity after 2 s . .

A horizontal conveyor belt moves with a constant velocity V.A small block is projected with a velocity of 6m//s on it in a direction opposite to the direction of motion of the belt The block comes to rest relative to the belt in a time 4s. mu =0.3, g =10 .m//s^(2) Find V .

A particle is projected from ground with velocity 40sqrt(2)m//s at 45^(@) . At time t=2s

A block is projected upwards with a velocity of 5 m/s from the bottom of a rough inclined plane of inclination 30° with the horizontal. It stops after 0.5 s. What is the coefficient of friction ? (g =10m//s^2 )

A particle is projected with velocity of 10m/s at an angle of 15° with horizontal.The horizontal range will be (g = 10m/s^2)

A particle is projected with velocity 20sqrt(2)m//s at 45^(@) with horizontal. After 1s (g=10m//s^(2)) match the following table

A particle is projected with a velocity of 10sqrt2 m//s at an angle of 45^(@) with the horizontal. Find the interval between the moments when speed is sqrt125 m//s(g=10m//s^(2))