A block of mass 0.5 kg has an initial velocity of `10ms^(-1)` down an inclined plane of angle `30^@`, the coefficient of friction between the block and the inclined surface is 0.2. The velocity of the block after it travels a distance of 10 m is

A block is stationary on an inclined plane If the coefficient of friction between the block and the plane is mu then .

An ice cube is kept on an inclined plane of angle 30^(@) . The coefficient to kinetic friction between the block and incline plane is 1//sqrt(3) . What is the acceleration of the block ?

A block of mass 2kg rests on a rough inclined plane making an angle of 30^@ with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is

A block of mass m slides down an inclined plane of inclination theta with uniform speed. The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is

A block of mass m slides down an inclined plane of inclination theta with uniform speed The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is .

A track has two inclined surface AB and DC each of length 3 m and angle of inclination of 30^@ with the horizontal and a central horizontal part of length 4m shown in figure. A block of mass 0.2 kg slides from rest from point A. The inclined surfaces are frictionless. If the coefficient of friction between the block and the horizontal flat surface is 0.2, where will the block finally come to rest ? [in 10^(-1) m ]

Two blocks of masses 2kg and M are at rest on an inclined plane and are separated by a distance of 6.0m as shown. The coefficient of friction between each block and the inclined plane is 0.25 . The 2kg block is given a velocity of 10.0m//s up the inclined plane. It collides with M, comes back and has a velocity of 1.0m//s when it reaches its initial position. The other block M after the collision moves 0.5m up and comes to rest. Calculate the coefficient of restitution between the blocks and the mass of the block M. [Take sintheta=tantheta=0.05 and g=10m//s^2 ]

A block of mass m=4kg is placed oner a rough inclined plane as shown in figure. The coefficient of friction between the block and the plane is mu=0.5 . A force F=10N is applied on the block at an angle of 30^(@) .

A block of mass m sides down an inclined right angled trough .If the coefficient of friction between block and the trough is mu_(k) acceleration of the block down the plane is