A proton and an `alpha` particle are accelerated through the same potential difference V. The ratio of their de Broglie wavelengths is

A proton and an alpha -particle are accelerated through same potential difference. Find the ratio of their de-Brogile wavelength.

A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha -particle is

A proton and an alpha particle are accelerated through the same potential difference. The ratio of the wavelengths associated with the proton to that associated with the alpha particle is

An electron and a proton are accelerated through the same potential difference. The ratio of their de-Broglie wavelengths will be

An electron and a proton are accelerated through the same potential difference. The ratio of their de broglic wavelengths will be

A proton and and alpha - particle are accelerated through a potential difference of 100 V . The ratio of the wavelength with the proton to that associated to that associated with an alpha - particle is

A proton and an alpha -particle are accelerated, using the same potential difference. How are the de-Broglie wavelengths lambda_(p) and lambda_(a) related to each other?

An electron of mass m_e and a proton of mass m_p are accelerated through the same potential difference. The ratio of the de Broglie wavelength associated with an electron to that associated with proton is