If matrix `A=[a_(ij)]_(3xx)`, matrix `B=[b_(ij)]_(3xx3)`, where `a_(ij)+a_(ji)=0` and `b_(ij)-b_(ji)=0 AA i`, `j`, then `A^(4)*B^(3)` is

If matrix A = [a_(ij)]_(3xx3), matrix B= [b_(ij)]_(3xx3) where a_(ij) + a_(ij)=0 and b_(ij) - b_(ij) = 0 then A^(4) cdot B^(3) is

Statement-1 (Assertion and Statement- 2 (Reason) Each of these questions also has four alternative choices, only one of which is the correct answer. You have to select the correct choice as given below. Statement - 1 If mateix A= [a_(ij)] _(3xx3) , B= [b_(ij)] _(3xx3), where a_(ij) + a_(ji) = 0 and b_(ij) - b_(ji) = 0 then A^(4) B^(5) is non-singular matrix. Statement-2 If A is non-singular matrix, then abs(A) ne 0 .

Construct a matrix [a_(ij)]_(3xx3) , where a_(ij)=2i-3j .

Construct a matrix [a_(ij)]_(2xx2) where a_(ij)=i+2j

Construct a matrix [a_(ij)]_(3xx3) ,where a_(ij)=(i-j)/(i+j).

If matrix A=[a_(ij)]_(3xx2) and a_(ij)=(3i-2j)^(2) , then find matrix A.

Write down the matrix A=[a_(ij)]_(2xx3), where a_ij=2i-3j

If a square matrix A=[a_(ij)]_(3 times 3) where a_(ij)=i^(2)-j^(2) , then |A|=