`CH_(3)-overset(O)overset(||)C-H``overset(HCN) (rightarrow)` `Aoverset(H_(3)O^(+))(rightarrow) B` .The number of oxygen atoms in the product `B` is

Ch_(3)-overset(O)overset(||)C-overset(O)overset(||)C-Phoverset(CH_(3)CO_(3)H)rarr product, Product will be :

H_(3)C-Mg-Br+H_(2)C=CH-overset(O)overset(||)(C)-H overset(H_(3)O^(+))to product?

C_(6) H_(5)CH_(3)overset((1)CrO_(2)Cl_(2)//CS_(2))underset(H_(3)O^(+))rightarrow (A) overset(OH^(-))rightarrow (B) The Conversition of A to B is called as

Evaluate the type of hybridisaton of carbon atoms marked with star. (a) overset(**)"C"H_(2)=CHoverset(**)-overset(O)overset(||)C-O-H (b) CH_(3)-overset(**)"C"H_(2)-OH (c) CH_(3)-CH_(2)-overset(O)overset(||)Coverset(**)-H (d) overset(**)"C"H_(3)-CH=CH-CH_(3) (e) CH_(3)-overset(**)C-=CH Number of carbon atoms of hybridisation : Type-I = x Type-II = y Type-III = z If x gt y gt z, then find xy - z

H-overset(O)overset(||)C-overset(O)overset(||)C-Hoverset(CH_(3)MgBr(excess))underset(H_(3)^(⊕)O)rarr Product :

CH_(3) - overset(O)overset(||)(C) - H and Ph-overset(O)overset(||)(C)-H can be differentiated by :