The average force necessary to stop a hammer with momentum p (in N-s) in 0.5 s is :-

The average force necessary to stop a hammer with 50 NS momentum in 0.05 s is

The average force necessary to stop a bullet of mass 20 g moving with a speed of 250 m//s , as it penetrates into the wood for a distance of 12 cm is

The velocity of a body of mass 10 kg increases from 4 m/s to 8 m/s when a force acts on it for 2 s (a) What is the momentum before the force acts? (b) What is the momentum after the force acts ? (c ) What is the gain in momentum per second ? (d) what is the value of the force ?

If a force 200N acts on a body, the change in momentum is 100 kg m/s. What is the time for which the force acts on th body?

Orbital angular momentum of 3s and 3p are :

A heavy box is slid across a rough floor with an initial speed of 4 m/s. It stops moving after 8 seconds. If the average resisting force of friction is 10 N, the mass of the box (in kg) is

A body moving with uniform velocity is stopped in 0.25 second by applying a retarding force of 200 Newton. The intial momentum of the body will be :-

A hammer of mass 500g , moving at 50m//s , strikes a nail. The nail stops the hammer in a very short time of 0.01 s . What is the force of the nail on the hammer?