`A(3,4,6)`,`B(0,4,3)`,`C(a,6,b)`are the vertices of a triangle ABC such that the median through A is equally inclined to the coordinate axes,then `a+b` is

A(2,3,5),B(-1,3,2),C( lambda ,5, mu ) are the vertices of a triangle.If the median through A is equally inclined to co-ordinate axes then the value of 3 lambda-2 mu is

Let A(2, 3, 5), B(-1, 3, 2), C(lambda, 5, mu) are the vertices of a triangle and its median through A(I.e.,) AD is equally inclined to the coordinates axes. Q. Projection of AB onBC is

Let A(2, 3, 5), B(-1, 3, 2), C(lambda, 5, mu) are the vertices of a triangle and its median through A(I.e.,) AD is equally inclined to the coordinates axes. Q. On the basis of the above information answer the following Q. The value of 2lambda-mu is equal to

If A(-3,0),B(4,-1),C(5,2) are vertices of triangle ABC, then the length of altitude through A is

A(5, 4), B(-3, -2) and C(1,-8) are the vertices of a triangle ABC. Find the equation of median AD

If A(-2,1),B(2,3) and C(-2,-4) be the vertices of a triangle ABC , show that tan B=(2)/(3)

If A(5,-1),B(-3,-2) and (-1,8) are the vertices of triangle ABC,find the length of median through A and the coordinates of the centroid.

If A(6,2),B(4,2)andC(6,4) are the vertices of DeltaABC , then find the length of the median through C.

If A(2,2),B(-4,-4) and C(5,-8) are the vertices of a triangle,then the lengthof the median through vertex C is.