The displacement-time equation of a particle executing SHM is `x-Asin(omegat+phi)`. At tme t=0 position of the particle is x=`A/2` and it is moving along negative x-direction. Then the angle `phi` can be

The displacement-time equation of a particle executing SHM is A-Asin(omegat+phi) . At tme t=0 position of the particle is x= A/2 and it is moving along negative x-direction. Then the angle phi can be

The displecemen-time equation of a particle execitting SHM is x = A sin (omega t + phi) At time t = 0 position of are position is x = A//2 and it is moving along negative x- direction .Then the angle phi can be

Displacement-time equation of a particle execution SHM is x=A sin( omegat+pi/6) Time taken by the particle to go directly from x = -A/2 to x = + A/2 is

Displacement-time equation of a particle executing SHM is x=A sin (omega t+(pi)/6) Time taken by the particle to go directly from x=-A/2"to"x=+A/2

Displacement time equation of a particle executing SHM is, x = 10 sin ((pi)/(3)t+(pi)/(6))cm . The distance covered by particle in 3s is

Displacement-time graph of a particle executing SHM is as shown The corresponding force-time graph of the particle can be

A particle executes SHMx=Asin(omegat+phi) . At t=0 , the position of the particle is x=(sqrt3A)/(2) and it moves along the positive x-direction. Find (a) phase constant phi (b) velocity at t=pi/omega (c) acceleration at t=pi/omega

The equation of motion of a particle executing SHM is ((d^2 x)/(dt^2))+kx=0 . The time period of the particle will be :

A particle executes simple harmonic motion of amplitude A along the x - axis. At t = 0 , the position of the particle is x = (A)/(2) and it moves along the positive x - direction. Find the phase contant delta , if of the equation is written as x = Asin (omega t + delta) .

If the displacement of a particle executing S.H.M. is given by x = 0.24 sin (400 t + 0.5)m, then the maximum velocity of the particle is