`y-cos y=x:(y sin y+cos y+x)y'=y` .

Solve the following differential equations y{x cos (y/x)+y sin (y/x)}dx- x{ y sin (y/x)-x cos (y/x)}dy=0 .

cos (x + y), sin (x + y), - cos (x + y) sin (xy), cos (xy), sin (xy) sin2x, 0, sin2y] | = sin2 (x + y)

What ( sin x cos y + cos x sin y) (sin x cos y - cos x sin y) equal to ?

prove that: cos ^ (2) x + cos ^ (2) y-2cos x * cos y * cos (x + y) = sin ^ (2) (x + y)

[x cos (y / x) + y sin (y / x)] y- [y sin (y / x) -x cos (y / x)] x (dy) / (dx) = 0

If y=y(x) is the solution of the equation e^(sin y) cos y""(dy)/(dx) +e^(sin y) cos x = cos x,y (0)=0, then 1+y ((pi)/(6)) +( sqrt(3))/(2) y((pi)/(3)) +(1)/( sqrt(2)) y((pi)/(4)) is equal to

The value of the expression 1- (sin^(2)y)/(1+ cos y) + (1+ cos y)/(sin y) -(sin y)/(1- cos y) is

if y+cos y=sin x , (dy)/(dx)=

[x (cos y) / (x) + y (sin y) / (x)] y = [y (sin y) / (x) -x (cos y) / (x)] x ((dy) / (dx))

Prove that : (sin (x+y))/(sin (x-y) )= (sin x. cos y + cos x . Sin y)/(sin x. cos y-cos x. sin y)