Orthogonal trajectories of the family of curves `x^2 + y^2 = c^2`

Orthogonal trajectories of the family of curves x^(2)+y^(2)=a is an arbitrary constant is

Find the orthogonal trajectories of family of curves x^(2)+y^(2)=cx

The orthogonal trajectories of the family of curves y=Cx^(2) , (C is an arbitrary constant), is

Orthogonal trajectories of the family of curves represented by x^(2)+2y^(2)-y+c=0 is (A) y^(2)=a(4x-1)(B)y^(2)=a(4x^(2)-1)(C)x^(2)=a(4y-1)(D)x^(2)=a(4y^(2)-1)

The orthogonal trajectories of the family of curves an a^(n-1)y=x^(n) are given by (A)x^(n)+n^(2)y= constan t(B)ny^(2)+x^(2)=constan t(C)n^(2)x+y^(n)=constan t(D)y=x

The orthogonal trajectories of the family of circles given by x^(2)+y^(2)-2ay=0, is

The orthogonal trajectories of the family of curves y=a^nx^n are given by (A) n^2x^2+y^2 = constant (B) n^2y^2+x^2 = constant (C) a^nx^2+n^2y^2 = constant (D) none of these

If the orthogonal trajectories of the family of curves e^(n-1)x=y^(n) .(where e is a parameter) always passes through (1, e) and (0, 0) then value of n is

A family of curves is such that the slope of normal at any point (x, y) is 2(1-y). The orthogonal trajectories of the given family of curves is