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0.365g of HCl gas was passed through 100...

0.365g of HCl gas was passed through `100 cm^(3)` of 0.2 M NaOH solution. The pH of the resulting solution would be:

A

1

B

5

C

8

D

13

Text Solution

Verified by Experts

The correct Answer is:
D
Moles of `HCl = 0. 365`
Moles of `NaOH = 100 xx 0.2 = 20`
Moles of NaOH left `= 19. 635 = 20`
Moles of NaOH per litre `= ( 20 xx 10 ^(-3) xx 1000)/(1000)`
`pOH = - log (2 xx 10 ^(-2))`
`= 1.7000 = 1.000`
`pOH =1`
`pH = 14- 1 = 13`
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