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E (cu) ^(@) = 0.34 V, E (zn) ^(@) = 0.76...

`E _(cu) ^(@) = 0.34 V, E _(zn) ^(@) = 0.76 V.` A Daniel cell contains` 0.1M ZnSO_(4)` solution and 0.01M CuSO4 solution at its electrodes. EMF of the cell is

A

`a)1.10 V`

B

`b)1.04`

C

`c) 1.16 V`

D

d)1.07 V`

Text Solution

Verified by Experts

The correct Answer is:
A
`Cu ^(2_) + 2e ^(-) to Cu, " " E ^(@) = 0.34`
`Zn ^(2+) + 2e ^(-) to Zn, " "E ^(@) = 0.76`
In the cell,
`Cu | underset("anode") ( Cu ^(2+))|| underset( "cathode") (Zn ^(2+))|Zn`
In the cell,
`E _("cell") ^(@) = E _("cathode") ^(@) - E _("anode") ^(@) `
`= 0. 76 - ( - 0.34) = 1. 10 V`
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