Commercial 11.2 volume `H_(2)O_(2)` solution has a molarity of :

Options

A. a) 1.0`
B. b) `0.5`
C. c) 11.2`
D. d) 1.12`

Answer

A

Explanation

1 mL `H _(2)O _(2)` solution gives `11.2 mL O _(2)` at NTP
`therefore 100 mL H _(2) O _(2)` solution gives `O _(2) = 100 xx 11.2 `
`= 1120. 0 mL O _(2) at NTP`
`H _(2)O_(2)` decomposes as
`2 H _(2) O _(2) (l) to 2 H _(2) O _(2) (l) + O _(2) (g)`
`because 22 400 m L O (2) ` at NTP is obtained from `68 g H _(2)O _(2)`
`therefore 1 m L O _(2)` at NTP is obtained from
`= ( 68)/( 22 400) g H _(2) O _(2)`
`therefore 1120 m L O_(2)` at NTP is obtained from
`= ( 68)/(22400) xx 1220`
`= 34 g`
`w = ( M xx m xx v )/(1000)`
`M = 1. 0`