Home
Class 12
CHEMISTRY
At 500K, the half-life period of a gaseo...

At 500K, the half-life period of a gaseous reaction at an initial pressure of 80 kPa is 350 s. When the pressure is 40 kPa, the half-life period is 175 s. The order of the reaction is

A

a) zero

B

b) one

C

c) two

D

d) three

Text Solution

Verified by Experts

The correct Answer is:
A
`p_(1)=80kPa,(t_(1//2))_(1)=350s`
`p_(2)=40kPa,(t_(1//2))_(2)=175s`
`(80)/(40)=(350)/(175)=2`

`because (p_(1))/(p_(2))=((t_(1//2))_(1))/((t_(1//2))_(2))=(a_(1))/(a_(2))`
`therefore =t_(1//2)propa` (zero order reaction)
Note For `n^(th)` order reaction
`t_(1//2)prop(1)/((a)^(n-1))`
Promotional Banner

Similar Questions

Explore conceptually related problems

At 500 K, the half life period of a gaseous reaction at an initial pressure of 80 kPa is 350 sec. When the pressure is 40 kPa, the half life period is 175 sec, the order of the reaction is:

AT 300 K, the half-life of a sample of a gaseous compound initially at 1 atm is 100 sec. When the pressure is 0.5 atm, the half-life is 50 sec. The order of reaction is :

The half-life of a second-order reaction is

The half life period of a reaction of first order is 100 sec. Calculate its rate constant.

The first order reaction has a half-life period of 34.65 seconds, its rate constant is

The half-life period of a first-order reaction is 15 minutes. The amount of substance left after one hour will be,

The half life of a reaction is halved as the intial concentration of the rectant is doubled. The order of the reaction is