An aromatic hdrocarbon with empirical formula `C_(5)H_(4)` on treatment with concentrated `H_(2)SO_(4)` gave a monosulphonic acid. 0.104 g of the acid required 10 mL of `(N)/(20)` NaOH for complete neutralisation. The molecular formula of hydrocarbon is

Options

A. `a) C_(5)H_(4)`
B. b) `C_(10)H_(8)`
C. `c) C_(15)H_(12)`
D. `d) C_(20)H_(16)`

Answer

C

Explanation

Empirical formula `(C_(5)H_(4))+H_(2)SO_(4)rarr` Monosulphonic acid
0.104 g of acid required 10 mL of `(N)/(20)` NaOH for completely neutralisation
`(0.104)/(n(5xx12+4xx1))=(1)/(20)xx10xx10^(-3)`
`n=(104)/(32)=3.25~~3`
The molecular formula of hydrocarbon will be `C_(15)H_(12)`.