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The equilibrium constant for the reactio...

The equilibrium constant for the reaction
`2NO_(2)(g)iff2NO(g)+O_(2)(g)" is "2xx10^(-6)" at "185^(@)C`. Then the equilibrium constant for the reaction, `4NO(g)+2O_(2)(g)rarr2NO_(2)(g)` at the same temperature would be

A

a) 2.5x10^(-5)`

B

b)`4xx10^(-12)`

C

c)`2.5xx10^(11)`

D

d)`2xx10^(6)`

Text Solution

Verified by Experts

The correct Answer is:
C
`2NO_(2)(g)iff2NO(g)+O_(2)(g)`
`K=([NO]^(2)[O_(2)])/([NO_(2)])=2xx10^(-6)`
`4NO_(2)(g)+2O_(2)(g)iff4NO_(2)(g)`
`K.=([NO_(2)]^(4))/([NO]^(4)[O_(2)]^(2))`
`=(1)/((K)^(2))`
`=(1)/((2xx10^(-6))^(2))`
Equilibrium constant `K.=0.25xx10^(12)`
`=2.5xx10^(11)`
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