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The percentage of an element M is 53 ...

The percentage of an element M is 53 in its oxide of molecular formula `M_(2)O_(3)` . Its atomic mass is about

A

a) 45

B

b) 9

C

c) 18

D

d) 27

Text Solution

Verified by Experts

Percentage of element M in `M_(2)O_(3)=53`
Let the atomic mass of M=x
Mass of M in`M_(2)O_(3)=2x`
Total atomic mass of `M_(2)O_(3)=2x+16xx3=2x+48`
Percentage of an element
`=("Mass of an element in a compound")/("Total mass of compound ")xx100`
`53=(2x)/(2x+48)xx100`
`53(2x+48)=200x`
`x=27`
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