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The pH of a solution obtained by mixing ...

The pH of a solution obtained by mixing 50 mL of 1 N HCl and 30 mL of 1 N NaOH is [log 2.5 =0.3979]

A

a)`3.979`

B

b)`0.6021`

C

c)`12.042`

D

d)`1.2042`

Text Solution

Verified by Experts

The correct Answer is:
B

Concentration of mixture ,br> `("conc of acid "xx"its volume - conc of base"xx"its volume")/("Total volume")`
`N=(N_(1)V_(1)-N_(2)V_(2))/(V_(1)+V_(2))`
`=(50xx1-30xx1)/(50+30)`
`=(20)/(80)`
`=(1)/(4)`
`=0.25`
Since HCl is in excess , so mixture is acidic and mixture contains `[H^(+)]` ion . Thus ,
`[H^(+)]=0.25`
`pH=-log[H^(+)]`
`=-log0.25`
`=0.6021`
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