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Plot of log x/m against log p is a str...

Plot of log x/m against log p is a straight line inclined at an angle of `45^(@)` . When the pressure is 0.5 atm and Freundlich parameter , k is 10 , the adsorbent will be (log 5=06990)

A

a) 1g

B

b) 2g

C

c) 3g

D

d) 5g

Text Solution

Verified by Experts

The correct Answer is:
D
Freundlich adsorption isotherm equation is
`(x)/(m)=kp^(1//n)`
On taking log both sides
`"log"(x)/(m)="log"k+(1)/(n)logp`
`"log"(x)/(m)="log"10+(1)/(n)"log"0.5`
`(because"slope"=(1)/(n)=tan theta= tan 45^(@)=1)`
`"log"(x)/(m)=1+(1)/(1)"log"(5xx10^(-1))`
`"log"(x)/(m)=1-0.6990+1`
`=0.6990`
`(x)/(m)=5.00`
`=5g`
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