Of the isomeric hexanes the isomers that give the minimum and maximum number of monochloroderivatives are respectively

Options

A. 3- methylpentane and 2,3 - dimethylbutance
B. 2,3 dimethybutane and n- hexane
C. 2,2 dimethylbutance and 2- methylpentane
D. 2,3 dimenthylbutane and 2- methylpentane

Answer

D

Explanation

The possible isomers of hexane are

Out of these structure (iii) and (i) have respectively minimum and maximum number of monochloroderivatives
For structure (iii),

[Only 2 monochlorodervatives (minimum ) are possible]
For structure (i) ,

[ 5 monochlorodervatives (maximum) are possible]