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The number of photons emitted per second...

The number of photons emitted per second by a 60W source of monochromatic light of wavelength 663nm is

A

a) 4 times 10^-20`

B

b) `1.5 times 10^20`

C

c) `3 times 10^-20`

D

d) `2 times 10^20`

Text Solution

Verified by Experts

The correct Answer is:
D

Energy `E=(nhc)/lamda`
`implies 60 times1Js= (n times 6.63 times 10^-34 Js times 3 times 10^8m)/(663 times 10^-9m)`
`therefore n=(60 times 1 times 663 times 10^-9)/(6.63 times 10^-34 times 3 times 10^8)`
`=2 times 10^20`
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