Among the following species , identify the pair having same bond order `CN^-, O_2^(-), NO^(+), CN^(+)`

Options

A. a)`CN^(-) and O_2^(-)`
B. b)`O_2^(-) and NO^(+)`
C. c)`CN^(-) and NO^(+)`
D. d)`CN^(-) and CN^(+)`

Answer

C

Explanation

Species having the same number of electrons, have same bond order.

Since, `CN^-` and `NO^+` have same number of electrons, they have same bond i.e, 3.
`CN^-` or `NO^+` `=14=sigma1s^2,sigma^+ 1s^2,sigma2s^2,sigma^., 2s^2,sigma2p_s^2,pi2p_x^2=pi2p_y^2`
Bond order `=(N_b-N_a)/2=(10-4)/2=3`