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A compound in which a metal ion M^(x+) (...

A compound in which a metal ion `M^(x+) (Z=25)` has a spin only magnetic moment of `sqrt(24)BM`. The number of unpaired electrons in the compound and the oxidation state of the metal ion are respectively

A

4 and 2

B

5 and 3

C

3 and 2

D

4 and 3

Text Solution

Verified by Experts

The correct Answer is:
D
Spin only magnetic moment
`mu=sqrt(n(n+2))=sqrt24`
`impliesn^2+2n-24=0`
`(n+6)(n-4)=0`
`therefore n=4`
[`because n=-6` not possible]
Here , n is the number of unpaired electrons.
The electronic configuration of the metal ion `M^(x+)` is
`Z(25)=1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^5`
Since four unpaired electrons are present, the oxidation state must be +3.
`therefore Z^(3+) (25)=1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^4`
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