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Energy released, when one atm of uranium...

Energy released, when one atm of uranium undergoes nuclear fission according to the following reaction is about
`_92 U^(235)+_0n^l to _56 Ba^(144) +_36 Kr^(90) +2_0 n^1`

A

235MeV

B

200MeV

C

931.5MeV

D

`5.33 times 10^23` MeV

Text Solution

Verified by Experts

The correct Answer is:
B
Mass defect , `Delta m= sum` mass of reactants `-sum` mass of products
`Delta m=235.060-(143.881+89.947+1.009)`
=0.223
Binding energy or the energy released.
`=0.223 times 931 MeV`
`=207.6 MeV`
=208 MeV
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