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When 0.2g of 1 butanol was burnt in a su...

When 0.2g of 1 butanol was burnt in a suitable apparatus, the heat evolved was sufficient to raise the temperature of 200g water by `5^@C`. The enthalpy of combustion of 1 butanol in `kcal mol^-1` will be

A

`+37`

B

`+370`

C

`-370`

D

`-740`

Text Solution

Verified by Experts

The correct Answer is:
C
Heat required to raise the temperature of 200g water by `5^@C`
m.c. `Delta t`
`=200 times 1 times 5=1000 cal =1 kcal`
`therefore` 0.2g 1 butanol on burning liberates=1 kcal heat
`therefore 74 g(1 mol)` 1 butanol or burning will liberate
`=1/0.2 times 74`
`=370`
Since, the heat is liberated `Delta H=-370kcal`
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