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An 1% solution of KCl (l), NaCl (II), Ba...

An 1% solution of KCl (l), NaCl (II), `BaCL_ (III) and urea (IV) ` have their osmotic pressure at the same temperature in the ascending order (molar masses of NaCl, Kcl , `BaCl_2` and urea are respectively 58.5, 74.5, 208.4 and 60g `mol^-`) Assume 100% ionization of the electrolytes at this temperature

A

`I lt III lt II lt IV`

B

`III lt I lt II lt IV`

C

`I lt II lt III lt IV`

D

`III lt IV lt I lt II`

Text Solution

Verified by Experts

The correct Answer is:
D
`1%` solution means 1g solute is present in 100mL of water.
Osmotic pressure, `pi= (I w times RT)/(M times V)`
`therefore pi_(KCl)= (2 times 1 times 1000 times RT)/ (74.5 times 100)`
`=2 times 0.134 RT`
`pi_(NaCl)= (2 times 1 times 1000 times RT)/(58.5 times 100)`
`=2 times 0.171 RT`
`pi_(BaCl_2)= (3 times 1 times 1000 times RT)/(208.4 times 100)`
`pi_(urea)= (1 times 1 times 1000 times RT)/(60 times 100)`
`=1 times 0.167 RT`
SInce temperature is same all cases, the ascending order of osmotic pressure is
`III lt IV lt I lt II`
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