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What is the overall formation equilibriu...

What is the overall formation equilibrium constant for the ion `[ML_4]^(2-)` ion, given that `beta_4` for this complex is `2.5 times 10^13`

A

a)`2.5 times 10^13`

B

b)`5 times 10^-19`

C

c)`2.5 times 10^-14`

D

d)`4.0 times 10^-13`

Text Solution

Verified by Experts

The correct Answer is:
A
`beta_4` for `[ML_4]^(2-)` can be written as
`beta_4= [ML_2]^(2-)/([M^(2+)][L^-1]^4)=2.5 times 10^13`
The overall formation equilibrium constant can be written as
`k_n=[ML_2]^(2-)/([M^(2+)][L^-1]^4)`
`k_n=beta_4=2.5 times 10^13`
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