Arrange the following in the order of increasing mass (atomic mass O = 16, Cu = 63, N = 14)
I. One atom of oxygen
II. One atom of nitrogen
III. `1 xx 10^(-10)` mole of oxygen
IV. `1 xx 10^(-10)` mole of copper

Options

A. a) `II lt I lt III lt IV`
B. b) `I lt II lt III lt IV`
C. c) `III lt II lt IV lt I`
D. d) `IV lt II lt III lt I`

Answer

A

Explanation

I. One atom of oxygen `= 16 xx 1.66 xx 10^(-24)g`
II. One atom of nitrogen `= 14 xx 1.66 xx 10^(-24)g`
III. `1 xx 10^(-10)` mole of oxygen `= 32 xx 1 xx 10^(-10)g`
IV. `1 xx 10^(-10)` mole of copper `= 63 xx 1 xx 10^(-10)g`
Thus, the correct order of increasing mass
`II lt I lt III lt IV`