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In the disproportionation reaction 3HClO...

In the disproportionation reaction `3HClO_(3) rarr HClO_(4) + Cl_(2) + 2O_(2) + H_(2)O`, the equivalent mass of the oxidising agent is (molar mass of `HClO_(3)` = 84.45)

A

a) 16.89

B

b) 32.22

C

c) 84.45

D

d) 28.15

Text Solution

Verified by Experts

The correct Answer is:
A

This is a disproportionation reaction since here the oxidation state of chlorine decreases from +5 to 0 in `Cl_(2)` as well as increases from +5 to +7 in `HClO_(4)`. Thus, `HClO_(3)` acts as oxidising as well as reducing agent.
Equivalent mass of oxidising agent (i.e., `HClO_(3)`)
`= ("molar mass")/("Change in oxidation number")`
`= (84.45)/((5-0)) = 16.89`
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