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0.02 mole of [Co(NH(3))(5)Br]Cl(2) and 0...

0.02 mole of `[Co(NH_(3))_(5)Br]Cl_(2)` and 0.02 mole of `[Co(NH_(3))_(5)Cl]SO_(4)` are present in 200 cc of a solution X. The number of moles of the precipitates Y and Z that are formed when the solution X is treated with excess silver nitrate and excess barium chloride are respectively

A

0.02, 0.02

B

0.01, 0.02

C

0.02, 0.04

D

0.04, 0.02

Text Solution

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The correct Answer is:
D

`[Co(NH_(3))_(5)Br]Cl_(2)+2AgNO_(3)rarr`
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