Ethanoic acid on heating with ammonia forms compound A which on treatment with bromine and sodium hydroxide gives compound B. Compound B on treatment with `NaNO_(2)`/dil. HCl gives compound C. The compounds A, B and C are

Options

A. ethanamide, methanamine, methanol
B. propanamide, ethanamine, ethanol
C. N-ethylpropanamide, methaneisonitrile, methanamine
D. ethanamine, bromoethane, ethanediazoniumchloride

Answer

A

Explanation

`CH_(3)COOH+NH_(3)overset(Delta)rarrundersetunderset(.A.)("ethanamide")(CH_(3)CONH_(2))`
`underset(.A.)(CH_(3)CONH_(2))+Br_(2)+3NaOHrarrundersetunderset("amine .B.")("methyl")(CH_(3)NH_(2)) +Na_(2)CO_(3)+NaBr+H_(2)O`
`CH_(3)NH_(2)underset((NaNO_(2)"/dil HCl"))overset(HNO_(3))rarrundersetunderset(".C.")("methanol")(CH_(3)OH)`