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How many molecules of CO2 are formed whe...

How many molecules of `CO_2` are formed when one milligram of 100% pure `CaCO_3` is treated with excess hydrochloric acid?

A

`6.023 xx 10^(23)`

B

`6.023 xx 10^(21)`

C

`6.023 xx 10^(20)`

D

`6.023 xx 10^(18)`

Text Solution

Verified by Experts

The correct Answer is:
D
`underset(100g)(CaCO_3) +2HCI to CaCI_2 + H_(2) O + underset(1"mol")(CO_2)`
`because 100 "g CaCO"_3` gives, molecules of `"CO"_2 = 6.022 xx 10^(23)`
`therefore 1 xx 10^(-3) "g CaCO"_3` gives molecules of `"CO"_2`
`= (6.022 xx 10^(23) xx 1 xx 10^(-3) )/( 100)`
`= 6.022 xx 10^(18)`
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