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When 4 g of an ideal gas A is introduced...

When 4 g of an ideal gas A is introduced into an evacuated flask kept at 25°C, the pressure is found to be one atmosphere. If 6 g of another ideal gas B is then added to the same flask, the pressure becomes 2 atm at the same temperature. The ratio of molecular weight `(M_(A) : M_(B))` of the two gaused would be

A

`1:2`

B

`2:1`

C

`2:3`

D

`3:2`

Text Solution

Verified by Experts

The correct Answer is:
C
From ideal gas equation `(pV = nRT)`
`p prop n`
For same pressure, number of moles will be same.
`therefore n_A= n_B`
or `(W_A)/(m_A) = (w_B)/(m_B)`
or `(m_A)/(m_B) = (w_A)/(w_B) = (4)/(6) = (2)/(3)`
`therefore m_A : m_B = 2:3`
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