For the following reaction, `NO_(2) (g) + CO (g) to NO(g) + CO_(2) (g)` the rate law is
Rate = `k [ NO_2]^2`. If 0.1 mole of gaseous carbon monoxide is added at constant temperature to the reaction mixture which of the following statements is true?

Options

A. Both k and the reaction rate remain the same
B. Both k and the reaction rate increase
C. Both k and the reaction rate decrease
D. Only k increases, the reation rate remain the same

Answer

A

Explanation

`NO_(2) (g) + CO(g) to NO(g) + CO_(2) (g)`
`because` Rate of reaction, `((dx)/(dt)) = k[NO_(2)]^(2)`
`therefore` Rate is independent of CO.
Hence, on adding more CO to the reaction mixture, both k and rate remain the same.