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A(g) +3B (g) rArr 4C(g). Initially c...

`A(g) +3B (g) rArr 4C(g).`
Initially concentration of A is equal to that of B. The equilibrium concentration of A and C are equal .`K_c ` is :

A

` 0.08`

B

` 0.8`

C

` 8`

D

`80`

Text Solution

Verified by Experts

The correct Answer is:
C
` A(g) +3B ( g) hArr 4C (g) `
` {:( 1,1,0, (" initial concentration ")),((1-x),(1-3x),4x,(" final concentration ")):}`
(at equilibrium)
According to questions , ` 1-x = 4x `
` therefore " " x= (1)/(5)`
For above reactions
` K_c = ([C]^(4))/([A][B] ^(3))= ((4x)^(4))/((1-x) (1-3x)^(3) ) `
` K_c= ((4xx (1)/(5))^(4))/((1-(1)/(5) ) (1-3xx(1)/(5))^(3)) = 8.0`
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