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Two moles of PCl5 is heated in a closed ...

Two moles of `PCl_5` is heated in a closed vessel of 2L capacity. When the equilibrium is attained 40% of it has been found to be dissociated. What is the ` K_C` in mol/` dm^(3)`?

A

` 0.532`

B

` 0.266`

C

` 0.133`

D

` 0.174`

Text Solution

Verified by Experts

The correct Answer is:
B
Number of moles of `PCl_5` dissociated at equilibrium ` = 2xx 40//100 =0.8`
` PCl_5 hArr PCl_3 +Cl_2`
` 2mol " " 0" " 0 ` (initially)
(2-0.8) mol 0.8 mol (at equilibrium )
` [PCl_5] =[Cl_2] = (0.8)/(2)= 0.4 ML^(-1)`
` therefore K_c = ([PCl_3][Cl_2])/([PCl_5])= (0.4 xx 0.4)/(0.6)`
`= 0.267 mol//dm^(3)`
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