How much of sulphur is present in an organic compound if 0.53 g of the compound gave 1.158g of ` BaSO_4` on analysis?

Options

A. 0.1
B. 0.15
C. 0.2
D. 0.3

Answer

D

Explanation

% of S `= (32)/(233) xx (" wt. of " BaSO_4)/(" wt. of organic compound " ) xx 100 `
` = (32)/ ( 233) xx (1.158)/(0.53 ) xx100 `
`= 30% `