Calculate the energy released in joules in the following nuclear reaction : `""_(1)^(2)H + ""_(1)^(2)H to ""_(2)^(3)He + ""_(0)^(1)N` Assume that the masses of `""_(1)^(2)H, ""_(2)^(3)He` and neutron are 2.0141, 3.0160 and 1.0087 amu respectively.

Options

A. ` 0.018 ` amu
B. ` 0.18 ` amu
C. ` 0.0018` amu
D. ` 1.8 ` amu

Answer

A

Explanation

Total mass of
`_1^(2) H+_1^(3) H to +_2^(4) He+ _0^(1) n`
In the above reaction,
total mass of LHS =2.014 +3.016 =5.030
total mass of RHS = 5.012
Mass loss while forming the products
`= 5.030- 5.012`
` = 0.018` amu